思路:找「右侧第一个 ≤ cur」的元素 → 弹出所有 cur 的元素,栈顶即为折扣。最终价格 = cur - 折扣(有则)或 cur(无则)。
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If you just want to be told today's puzzle, you can jump to the end of this article for today's Connections solution. But if you'd rather solve it yourself, keep reading for some clues, tips, and strategies to assist you.
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